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Re: Neat Math
08-08-2007, 07:20 AM
That is -very- cool. How in the world did you figure it out?
I've got something similar...assuming I remember the math right.
1
[sigma](-1^x-1)/(2x-1) approaches Pi/4 as x goes to infinity.
infinity
...that looks really bad. If I'm dredging things out of my brain correctly, that's an infinite series that generates the following fractions.
1/1 - 1/3 + 1/5 - 1/7 + 1/9 - 1/11...
Greetings, fellow nerd.
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Re: Neat Math
08-08-2007, 10:10 PM
The fraction 271801/99990 = 2.7182818281828 is a good approximation for e ~= 2.71828182845904
Further, if you want to compute e to any accuracy, a good series for e is Sigma{n=0 to inf}[1/n!] = 1+1+1/2+1/6+1/24+1/120+1/720+
(derived from the Maclauren series for e^x: Sigma{n=0 to inf}[x^n/n!] = 1+x+x^2/2+x^3/6+x^4/24+x^5/120+ , which actually converges for all x)
Lastly, e can be defined as the limit as n -> inf of (1+1/n)^n, though that converges too slowly to make a good estimate (n=10000 gives 2.718145936).
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